Arectangular garden originally measured 5 feet by 10 feet as shown below. a path was created by increasing each side of the original rectangle by x-feet on both sides. if the area of the path that rings the garden is 54 square feet, find the value of x.

The area is given by
 A = (5 + 2x) * (10 + 2x) - 50
 Rewriting we have:
 A = 50 + 10x + 20x + 4x ^ 2 -50
 Rewriting we have:
 A = 4x ^ 2 + 30x
 Substituting the value of the area we have:
 54 = 4x ^ 2 + 30x
 Rewriting:
 4x ^ 2 + 30x - 54 = 0
 We look for the roots:
 x1 = -9
 x2 = 3/2
 We take the positive root:
 x2 = 3/2
 
 the value of x is:
 x = 3/2

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

ac ≅ ab (given)< cax ≅ < bax   (given)ax ≅ ax (common side)

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

ac ≅ ab (given)< cay ≅ < bay (since < cax ≅ < bax is given and xy is the extension of line ax)ay ≅ ay (common side)

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

The answer is 12 pizzas