What is the probability of flipping both heads with two different coin

1/4

Step-by-step explanation: Tossing two coins are independent events because the outcome of tossing one coin does not affect the outcome of tossing the other coin. We can find the probability of independent events by multiplying the probability of the first event by the probability of the second event. If we want to find the probability of tossing a heads and a heads, we multiply the probability of tossing a heads by the probability of tossing a heads.

Now, let's find the probability of tossing a heads on the first coin. Remember that a coin has two sides which are heads and tails. Since heads is one of the two sides, we can represent this as 1 out of 2 or 1/2. This would be the same for the second side as well which is 1/2.

Now, we can simply multiply 1/2 by 1/2 and we will get the fraction 1/4. Therefore, the probability of tossing heads and heads is 1/4.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

i think there was a typo. you wrote pat brings 3 quarts of ice-cream to the party. each serving of ice-cream is 1 6 quart. how many total servings of ice-cream does pat bring to the party? i think the bold is supposed to be 1/6. so 1 quart of ice cream = 6 servings. 6 * 3 = 18.