Circle 1 has center (−6, 2) and a radius of 8 cm. circle 2 has center (−1, −4) and a radius 6 cm. what transformations can be applied to circle 1 to prove that the circles are similar? enter your answers in the boxes. enter the scale factor as a fraction in simplest form

"Circle 1 has center (−6, 2) and a radius of 8 cm. Circle 2 has center (−1, −4) and a radius 6 cm. What transformations can be applied to Circle 1 to prove that the circles are similar? Enter your answers in the boxes. Enter the scale factor as a fraction in simplest form"

The circles are similar because the transformation rule (x+5 y-6) can be applied to Circle 1 and then dilate it using a scale factor of 3/4

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.