Felicia wants to draw triangle pqr such that the conditions shown are true. i already did something as you can see , but im not sure where to go from bere and how to explain question a either. show how u got ur work. quickly if

Cos p = 3/5=0.6

Therefore, Hypotenuses, PR = 5 and height, h = 3

If this was a right angle triangle such that q=90°, then QR= sqrt (5^2-3^) = 4
and the area, A = 1/2*3*4 = 6 (this is against the conditions)

Lets assume that PQ=PR = 5, and h changes to Adjacent side to angle p= 3.
Then half QR = 3,

Now, h= Sqrt (5^2-3^2) = 4
The new triangle has an area of,

A= 1/2 (3*2)*4 = 3*4 =12 (different from 6 as required).
The triangle will look as the attached photo.