What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2? f(x) = x3 – x2 – 4x + 4 f(x) = x4 – 3x2 – 4 f(x) = x4 + 3x2 – 4 f(x) = x3 + x2 – 4x – 4

We are given roots of a polynomial function : i, –2, and 2.

And leading coefficient 1 .

We need to find the polynomial function of lowest degree.

Please note: We have one root i, that is a radical root. And a radical always comes in pair of plug and minus sign.

Therefore, there would be another root -i.

So, we got all roots of the polynomial function : i, -i, -2, and 2.

For the given roots, we would have factors of the polynomial (x-i)(x+i)(x+2)(x-2).

Now, we need to multiply those factors to get the polynomial function.

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0

c.)

step-by-step explanation: