Acylindrical container of four rubber balls has a height of 20 centimeters and a diameter of 5 centimeters. each ball in the container has a radius of 2.5 centimeters. find the amount of space in the container that is not occupied by rubber balls. round your answer to the nearest whole number.

The amount of space not occupied by the rubber balls is given by:

Volume=(volume of the container)-(volume of the rubber balls)

volume of the container is given by:

V=πr²h

V=π*(5/2)²(20)

V=392.70 cm³

Volume of each ball is:

V=4/3πr³

V=4/3π(2.5)³=65.45 cm³

volume of four balls

65.45×4=261.8 cm³

The volume of the container that is not occupied by the balls will be:

V=392.70-261.8

V=130.9 cm³

Thus, to the nearest whole number is 131 cm³. Hope this Helps!

Step-by-step explanation:

answer: i believe it’s 245.04

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b