How do i find the focus of the parabola from the equation x^2-12y=0?

so, first off, notice, the squared variable is the "x", meaning is a vertical parabola.

the coefficient of the x² is a positive value, thus the vertical parabola is opening upwards.

the vertex is at 0,0, namely the origin.

the "p" distance is 3.

so the focus point is 3 units above the vertex, and you surely know where that is.

X= 49; x = 4step 1: foilstep 2: equal both to 0step 3: find x individually