Consider the two functions given below. f(x) = 3x + 4 g(x) = 2^x - 1 which of the following pairs of transformations causes the graphs of the functions to have the same y-intercept? f(x) - 3 and g(x) + 1 f(x) + 4 and g(x) - 1 f(x) - 2 and g(x) + 1 f(x) + 3 and g(x) - 6

This means which transformation makes the same answer at x = 0

f(x) = 3x + 4


f(0) = 4
g(0) = 1 - 1 = 0

Which transformation makes 4 = 0?

4 + x = 0 + y

4 - 3 =0 + 1

1 = 1

Option 1 is your answer

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