Ineed asap plese what is the equation of an ellipse whose foci at (+/-6,0) and c/a=3/5

Consider this option:
the equation of ellipse is: x²/a² + y²/b² = 1
1. if focuses are (6;0) and (-6;0), it means, that 2c=6-(-6)=12, ⇒ c=6.
2. c²=a²-b², it means, that a²-b²=36 - this is the 1st equation.
3. if c/a=3/5, it means, that c²/a²=9/25, ⇒ (a²-b²)/a²=9/25 - this is the 2d equation.
4. the 1st and the 2d equations are the system of two equations:

5. the required equation of the ellipse is: