In 2000 the population of a city was 588292 people. in 2002 the population of the city increased to 599656, what is the population in 2008

The population in 2008 is 635,082. This is true given that we follow the 1.93% increase in population every two years. The rate was derived from the increase of 588,292 (year 2000) to 599,656 (year 2002). The computation is:

((599,656 - 588,292) / 588,292) * 100 = 1.93%

Applying the rate every two years, here's what get:

2000: 588,292
2002: 599,656
2004: 611,240
2006: 623,047
2008: 635,082

The answer would be c