An isosceles triangle has base 6 and height 11. find the maximum possible area of a rectangle that can be placed inside the triangle with one side on the base of the triangle. (hint: similar triangles may be of assistance.)

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

you would need to also lose 1 point for each of the other outcomes for it to be fair.

step-by-step explanation: