Which of the following describes the zeroes of the graph of f(x) = -x^5 + 9x^4 - 18x^3?

The complete question in the attached figurewe know thata is zero of a polynomial f(x), if f(a)=0step 1find the zerosf(x) = –x5 + 9x4 – 18x3 = x³ ( –x² + 9x – 18)= (x³)(x-3)(x-6)f(x) = –x5 + 9x4 – 18x3for x=0  f(0) =0  for x=3    f(3)=0 and for x=6  f(6)=0sothe zeros are0, 3 and 6step 2find the multiplicityf(x) = –x5 + 9x4 – 18x3 = x3 ( –x2 + 9x – 18)=(x-0)³(x-3)(x-6)the multiplicity is: 0 is a zero of multiplicity 33 is a zero of multiplicity 16 is a zero of multiplicity 1the answer is 0 with multiplicity 3, 3 with multiplicity 1, 6 with multiplicity 1

The answer to your question is 1/9