Plz mee due ! the equation x^2+px−35=0 has one root that is equal to 7. find the other root and the value of the coefficient p. x^2= x squared

We know that
x²+px−35=0-------> has one root that is equal to 7
so
substitute x=7 in the equation
7²+p*7−35=0
49+p*7−35=0
14+p*7=0
p=-14/7------> p=-2

the answer Part a) is 
the value of the coefficient p is -2

Part b) Find the other root
x²+px−35=0-----> x²-2x−35=0

using a graph tool-------> to resolve the second order equation
see the attached figure

the other root is
x=-5

the answer part b) is
 the value of  the other root is -5