Awarehouse's rectangular ceiling measures 12 meters by 18 meters, and is covered by acoustic tile squares which are one meter on a side. each piece of tile weighs a quarter of a kilogram. what will be the total weight of the tile required to cover the ceiling?

The first thing to do is find the rectangular warehouse area.
 We have then:
 A = (12) * (18) = 216
 A = 216 m ^ 2
 We now look for the area of each acoustic tile square:
 A '= (1) ^ 2 = 1
 A '= 1 m ^ 2
 We look for acoustic tile squares number:
 N = (A) / (A ')
 N = (216) / (1)
 N = 216
 Finally we look for the total weight:
 W = (1/4) * (216)
 W = 54 Kg
 
 The total weight of the tile required to cover the ceiling is:
 W = 54 Kg

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