Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 5.

The correct question is
Using the graph of f(x) = log2x below, approximate the value of y in the equation 2^(2y) = 5

we have 
2^(2y) = 5--------------> applying base 2 logarithm both members
2y*log2(2)=log2(5)
log2(2)=1
then
2y=log2(5)
y=[log2(5)]/2

using the graph
for  x=5  the approximate  value of log2(5) is 2.3
see the attached figure
so
y=[log2(5)]/2--------> y=[2.3]/2----------> y=1.15

the answer is
the approximate value of y is 1.15

300b(x) is graphed by the functio