What else would need to be congruent to show that abc = def by sas?

(A)AC=DF is correct

Step-by-step explanation:

It is given that AB=DE and ∠A=∠D and  we have to prove ΔABC≅ΔDEF, then

From ΔABC and ΔDEF, we have

AB=DE(given)

∠A=∠D(given)

AC=DF (because given triangles are congruent)

Thus, by SAS rule, ΔABC≅ΔDEF

Therefore, in order to prove that ΔABC≅ΔDEF by SAS rule, we need AC≅DF.

Thus, option A is correct.

x=30

step-by-step explanation:

0 is its x and y coordinate