Aquadratic function y = f ( x ) y=f(x) is plotted on a graph and the vertex of the resulting parabola is ( − 4 , − 5 ) (−4,−5). what is the vertex of the function defined as g ( x ) = f ( − x ) + 3 g(x)=f(−x)+3?

we know that

 g(x)=f(−x)+3

  that means

point (x,y) in the graph f(x) becomes a point (-x, y+3) in the graph g(x)

 therefore

 the point (-4,-5) > becomes a point (4,-5+3) > (4,-2)

the answer is

the vertex is the point (4,-2)

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)