Felicity recorded the number of laps she swam each month for 7 months. her data is shown. 112,134,150,98,120,68,116 which is the mean absolute deviation to the nearest whole number of felicity's lap data? a.16 b.18 c.20 d.36

The mean absolute deviation is 18.

We first find the mean.  Find the sum of all of the data points and divide by 7, the number of data points:

(112+134+150+98+120+68+116)/7 = 798/7 = 114

Now we subtract the mean from each data point, find the absolute value of each one, find their sum, and divide by the number of data points:

(|112-114|+|134-114|+|150-114|+|98-114|+|120-114|+|68-114|+|116-114|)/7
= (2+20+36+16+6+46+2)/7 = 128/7 = 18