Astudent solved the equation sin2x/cos x = 2, 0 ≤ x ≤ pi, and got pi/2. what was the student's error?

sin(2x)/cos x = 2sin x*cos x/ cos x = 2 sin x = 2

sin x = 1

x = pi/2

but cos pi/2 = 0

so the given equation is indeterminate for x = pi/2

Answer with Step-by-step explanation:

We are given a equation:

Now, we will solve it

 2sinx=2

 sinx=1

all the possible values of x from 0 to π so that sinx=1 is

  x=π/2

but, cos(π/2) is indeterminate

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

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