Two constructors working together finished building a room in 6 days. how long would it take for each constructor to build the room by himself, if it is known that one of them would require 9 more days than the other?

Step-by-step explanation:

Time to finish the room with both constructors: 6 days.

Time to finish the room by the first constructor only: x days.

Time to finish the room by the second constructor only: (x + 5) days.

If we associate all that, 1 day work of both constructors working at the same time would be

1 day work of the first is:

1 day work of the second is:

Now, we need to find the variable, using the following equation

Then, we need to find two numbers which product is 30, and which difference is 7. Those numbers are 10 and 3, because 10 times 3 is 30, and 10 minus 3 is 7.

Using the zero factor property, we have

But, only the positive number makes sense. Replacing the value in each expression we have

First constructor: days.

Second constructor: days,

Threfore, it would take 10 days to the first constructor and 15 days to the second one to finish the room.

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

it’s the first one your welcome