68x+p=qx+34 which values of p and q result in a equation with no solutions

Try this option:
1. if to re-write the given equation into the form -68x-34=qx-p and imagine it as two linear functions: y1=-68x-34 and y2=qx-p, then
2. according to the properties of linear function (y1||y2) q=-68 and p≠34. Note, if p=34, then y1≡y2.

p=34; q=-68

I'm just guessing, but my answer would c. 0 to 300.

The answer to your question is b’(16,14)