Mathematics, 27.07.2019 20:30 billgray2571
Give the equation of the circle that is tangent to the y-axis and center is (-3,2)
Answers: 1
![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{2}{ k})\qquad \qquad radius=\stackrel{3}{ r} \\\\\\\ [x-(-3)]^2+[y-2]^2=3^2\implies (x+3)^2+(y-2)^2=9](/tpl/images/0140/0693/c7ac0.png)
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Give the equation of the circle that is tangent to the y-axis and center is (-3,2)...
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