Simplify the following equation and show how: (2x+2)^3

You can use (a+b)2 = a2+2ab+b2.
(2x - 3)2 = (2x)2 + 2(2x)(-3) + (-3)2 = 4x2 - 12x + 9

Or you can use FOIL.

(2x - 3)2 = (2x - 3)(2x - 3) = (2x)2 + (2x)(-3) + (-3)(2x) + (-3)2 = 4x2 - 12x + 9

hope I could be helpful

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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