If the center of a circle is (1, 1), and it has a radius of 5, which is another point on the circle? a) (7, 1) b) (1, -5) c) (4, 5) eliminate d) (-2, 6)

We know that

the equation of a circle is
(x-h)²+(y-k)²=r²
where
(h, k) > is the center of a circle
r> is the radius
so
(h, k) (1, 1)
r=5
(x-1)²+(y-1)²=25

which is another point on the circle?
A)(7, 1)
(7-1)²+(1-1)²=25> (6)²+(0)²> 36 is not 25
point A is not on the circle

B)(1, -5)
(1-1)²+(-5-1)²=25> (0)²+(-6)²> 36 is not 25
point B is not on the circle

C)(4, 5)
(4-1)²+(5-1)²=25> (3)²+(4)²> 9+16> 25=25
point C is on the circle

D)(-2, 6)
(-2-1)²+(6-1)²=25> (-3)²+(5)²> 9+25> 34 is not 25
point D is not on the circle

the answer is 
the point C)(4, 5) is on the circle

I’m confused what’s happening