Use the quadratic formula to solve the equation. if necessary, round to the nearest hundredth. −5y2 + 2y = −2

1. The quadratic formula is applied to solve quadratic equations. This is:
 
 y=(-b±√(b²-4ac))/2a
 
 2. Therefore, you have:
 
 −5y²+2y=−2
 −5y²+2y+2=0
 
 a=-5
 b=2
 c=2
 
 3. When you substitute these values into the quadratic formula, you obtain:
 
 y=-2±√(2²-4(-5)(2))/2(-5)
 y=-2±√44/-10
 
 4. Therefore, you have: 
 
 y1=-0.46
 y2=0.86
 

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