Find the axis of symmetry of y=x^2-12x+8

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(x−5)2−33(x-5)2-33Reorder the right side of the equation to match the vertex form of a parabola.y=(x−5)2−33y=(x-5)2-33Since −5-5 does not contain the variable to solve for, move it to the right side of the equation by adding 55 to both sides.x=5x=5Use the vertex form, y=a(x−h)2+ky=a(x-h)2+k, to determine the values of aa, hh, and kk.a=1a=1h=5h=5k=−33k=-33Since the value of aa is positive, the parabola opens up.Opens UpFind the vertex (h,k)(h,k).(5,−33)(5,-33)Find pp, the distance from the vertex to the focus.Tap for more steps...1414Find the focus.Tap for more steps...(5,−1314)(5,-1314)Find the axis of symmetry by finding the line that passes through the vertex and the focus.x=5

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Y= -2x-1 the negative in front of the 2 is because the slope is negative and the -1 is because it’s down 1 on the y axis.