An observer (o) spots a plane flying at a 42° angle to his horizontal line of sight. if the plane is flying at an altitude of 15,000 ft., what is the distance (x) from the plane (p) to the observer (o)? a right triangle is shown with angle o marked 42 degrees, hypotenuse marked x and the height marked 15000 feet. 10,035 feet 16,648 feet 20,188 feet 22,417 feet

The distance (x) from the plane (P) to the observer (O) is:

22417 feet.

Step-by-step explanation:

The figure obtained by the use of the following given observation is attached to the answer.

We see that we will obtain a right angled triangle also the horizontal base angle is given to us.

We can use trignometric identity to find the distance between the observer on the ground and the plane i.e. the value of x.

We will use sine trignometric function to calculate the value of x.

Hence, value of x is:

which is approximately equal to:

x=22417 feet.

Hence, the distance (x) from the plane (P) to the observer (O) is 22417 feet.

22,417 feet so letter D

3; 9 is 8 to -4

step-by-step explanation: