What is the equation of a line that passes through(-6,2) and has a slope of -1/2 a. y=x/2-2 b. y= -x/2-1 c, y=2x+1 d. y=-2x-1

B.

Step-by-step explanation:

We are given that the equation of the line passes through the point (-6,2) and has a slope -1/2.

Substituting the given values in the formula for slope, we get,

i.e. =

i.e. -x-6 = 2y-4

i.e. 2y = -x-2

i.e.

Hence, the equation of the line is

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i