The perimeter of the base of a regular quadrilateral prism is 32 cm. the height of the prism is 2 times greater than the length of the base edge. find the sum of all edges of the prism.

The sum of all edges of the prism is 128 cm.

Step-by-step explanation:

It is given that the perimeter of the base of a regular quadrilateral prism is 32 cm. It means the base of the prism is a square.

Let the length of the base edge be a.

Perimeter of a square is 4a.

Divide both sides by 8.

The length of base edge is 8. It is given that the height of the prism is 2 times greater than the length of the base edge. It means the height of the prism is

The sum of all edges of the prism is

Length and breadth of the prism is 8 cm and height of the prism is 16 cm.

Therefore the sum of all edges of the prism is 128 cm.

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

so the possibilities of the measurement of the side of the triangle are either it is longest side or not the longest side

when it is the longest side

s < 25 + 35s < 60

if it is not the longest side

35 < 25 + s10 < sso 10 < s < 60so the perimeter70 < p < 130