Will give 20 the sum of the numerator and the denominator of the certain fraction is equal to 4,140. when the fraction was reduced, the result was 7/13. what was the original fraction?

Let's named variables n-numerator and d-denumerator

n+d=4,140 ∧  n/d=7/13 => n=(7/13)d

Then we replace n and get  (7/13)d+d=4,140 => (7/13)d +(13/13)d = 4,140

(20/13)d = 4,140 => d= (4,140 * 130) /20 = 2,691

n= (7/13) * 2,691 = 1,449

The original fraction is 1,449/2,691

Good luck!!!

Original fraction was where is a reduced common factor. We know that:



so original fraction:

I’d say d hope it