Acylindrical piece of iron pipe is shown below. the wall of the pipe is 1.25 inches thick, the width is 8 inches and the length is 14 inches, what is the approximate inside volume of the pipe?

The following steps should be taken to answer the problem.

1. Deduct from the diameter (d) the thickness of the wall's pipe of 1.25in. 

d = 8in - (2(1.25in))
   = 5.5in

2. Get the radius (r), which is half of the diameter.

r = 5.5in/2
  = 2.75in

3. Get the volume of the cylinder with the formula, V = πr²h

V = 3.14 × (2.75)² × 14in
   = 332.45in³

Thus, the iron pipe can hold approximately 332.45 cubic inches.

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.