Will give 99 points if answered asap

Part A

1.  Perimeter of the outside edges = 24 inches

2.  One possibility is: length = 8 in. and width = 8 in.

second possibility is: length = 16 in. and width = 4 in.

3.  Area of the wood portion = 11

4.  New dimensions are:

Length = 17.5 ft.

Width = 12.5 ft.

Part B

Area of the picture = 24

Area of the frame = 35

Step-by-step explanation:

Part A

1.  Perimeter of the outside edges = 2(length + width)

= 2(7 + 5)

= 2(12)

= 24 inches

2.  If the area of the frame was 64 , then the two possible dimensions are:

8 × 8 and 16 × 4

i.e., one possibility is: length = 8 in. and width = 8 in.

second possibility is: length = 16 in. and width = 4 in.

3.  Area of the wood portion = Area of the frame - Area of the picture

= (5 × 7) - (4 × 6)

= 35 - 24

= 11

4.  The scale factor is:

1 in. = 2.5 ft.

So, its length = 7 in. = 7(2.5) = 17.5 ft.

width = 5in. = 5(2.5) = 12.5 ft.

Part B:

Length of the picture = 6in.

Width of the picture = 4 in.

Area of the picture = Length × Width

= 6 × 4

= 24

Length of the frame = 7in.

Width of the frame = 5 in.

Area of the frame = 7 × 5 = 35

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