The access code for a car's security system consists of sixsix digits. the first digit cannot be zerozero and the last digit must be oddodd. how many different codes are available?

54 different codes should be right

You didn't say anything so I have to assume that other than the two conditions mentioned for the fist and last digit, all numbers 0-9 are permissible.

1st digit cannot be a 5. Therefore there are 9 possibilities
digits 2-5 can be any digit. There are 10 possibilities for each. There are 4 digits involved, so there are 104 possibilities.
Finally the last, 6th digit must be odd. Therefore there are 5 possibilities.

The number of different possible codes is
9 x 104 x 5 = 45 x 104 = 450,000

Your cleary not see the answer is 25

What are the following algebraic equations. you need to post those if you want the answer