If a rectangle's length is 7 more than 4 times the width and the perimeter is 54 what are the dimensions of the rectangle?

Let w = width of the rectangle 
4w+7 = length of the rectangle 

perimeter = 2 lengths + 2 widths 

2w + 2(4w+7) = 54 
2w + 8w + 14 = 54 
10w = 40 
w = 4 
4w+7 = 23 

dimensions of rectangle: 
width = 4 
length = 23 hope this helps

+1,000)=g7e=mc2-g=7 because if you know algebra you should know g=7 to get your answer

The answer would be (8+7z)/5