7.find the lengths of the missing sides in the triangle. if your answer is not an integer, leave it in simplest radical form. the diagram is not drawn to scale.

Here a right angled triangle given. one angle with measure given. The three sides of the triangle given 4, x, y.

We have to find, the sides which is opposite, adjacent and hypotenuse here.

We know that the side opposite to right angle is always hypotenuse. So, hypotenuyse = y.

The side adjacent to the given angle is x. So, here adjacent = x.

The opposite side is opposite to the given angle. So, opposite = 4.

Now we will use SOHCAHTOA that is , where x is the angle given.

To get x, we will use tan. So we will get,

We know the value of . By substituting the value we will get,

To find x, we have to move x here to the left side by multiplying it to both sides. We will get,

So we have got the value of x here.

Now to find y, we will use the trigonometric function sine.

we know the value of

By substituting the value we will get,

By cross multiplying we will get,

We will get y by dividing both sides by , we will get,

Now we will rationalize the denominator by multiplying to the top and bottom.

So we have got the required values of x and y.

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

hope to and hope that my answer is brainliest.(follow me )

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.