Lin has 13 coins in her pocket that equal 40 cents. all the coins are dimes, d, and pennies, p. which combination of coins does lin have? use the table to answer the question.

The combination of coins are:

         3 dimes and 10 pennies.

Let there are d number of dines and p number of pennies.

Now as there are a total of 13 coins this means that:

                   d+p=13(1)

and also the total value of the coins is 40 cents.

1 dime=10 cents

Hence, d dime= 10 d cents

Also, 1 penny= 1 cent

Hence p penny= p cents

Hence, we get:

                     10d+p=40(2)

On subtracting equation (1) from (2) we get:

             9 d=27

on dividing both side by 9 we get:

                 d=3

On putting the value of d in equation (1) we get:

           3+p=13

i.e.  p=13-3

i.e.  p=10

The combination is:

    3 dimes and 10 pennies

your answer is the last one

step-by-step explanation:

divide the length of a'c' by the length of ac to get a scale factor of two

& then reflect vertically (over the y-axis)

so your answer is dilation by a scale factor of 2 followed by reflection over the y-axis

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐