In a statistics class there are 11 juniors and 6 seniors; 2 of the seniors are females; 6 of the juniors are males. if a student is selected at random, what is the probability that the student is either a junior or a female? enter your answer as a fully reduced fraction.

Step-by-step explanation:

Given: Number of juniors = n(J)= 11

Number of seniors = 6

Total students n(S)=

Number of seniors are which are females =2

Number of  juniors are which are males =6

Then, number of juniors which are females =

Now, total females n(F)=

such that number of juniors which are females n(J∩F) =

Now, the number of students either a junior or a female is given by :_

Now, the probability that the student is either a junior or a female is given by :-

chiken

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.