Human body temperatures have a mean of 98.20° f and a standard deviation of 0.62° f. if a student is found to have a temperature of 99.5° f, find the z score and assess whether this temperature should be considered unusual.

The z-score for this temperature is 2.097.  The probability that a temperature would be greater than or equal to this temperature is 0.0179, or 1.79%.  This would be considered an unusual temperature.

Explanation


Using a z-table (http://www.z-table.com) we find the probability that a score is less than this to be 0.9821.  Thus the probability that a score is greater than or equal to this would be 1-0.9821=0.0179.

What's the denominator

He was paid 23 dollars for each lawn