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Mathematics, 29.07.2019 11:30 hannabeth91
F(x) = 2x2 – 4x – 3 0 = 2x2 – 4x – 3 3 = 2(x2 – 2x) 3 + 1 = 2(x2 – 2x + 1) 4 = 2(x – 1)2 2 = (x – 1)2 ± = x – 1 1 ± = x mica is solving for the zeros of a quadratic function by completing the square. her work is shown. what error did mica make? answer choices mica should have set each x = 0 instead of f(x). mica should have added 2 to 3 instead of 1. mica should have multiplied both sides by 2 instead of dividing. mica should have subtracted 1 from both sides instead of adding.
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F(x) = 2x2 – 4x – 3 0 = 2x2 – 4x – 3 3 = 2(x2 – 2x) 3 + 1 = 2(x2 – 2x + 1) 4 = 2(x – 1)2 2 = (x – 1)...
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