Suppose abcd is a rectangle. find ab and ad if point m is the midpoint of bc, am ⊥ md , and the perimeter of abcd is 34 in.. someone answered this question but ad is not 4 and ab is not 9. you

I substitute 1 in 2

AD²=2*[(17-AD)²+(AD/2)²]----> AD²=2*[289-34AD+AD²+0.25AD²]

AD²=578-68AD+2.50AD²--------> 1.50AD²-68AD+578

1.50AD²-68AD+578=0

 using a graph tool to solve the quadratic equation

see the attached figure

AD1=11.33 in

AD2=34 in----------is not solution because (AB+AD=17)

Solution is AD=11.33 in

AB=17-11.33--------> 17-11.33-----> AB=5.67 in

 the answer is

AD=11.33 in

AB=5.67 in

25

step-by-step explanation:

the answer is the third / last answer

step-by-step explanation: