Find the two-digit number which is 2 times the sum of its digits. find a statement and number, .

A two-digit number is twice the sum of its digit. If the tens digit is 7 less than the unit digit, find the number. 
Let x= the unit digit
Then y= the tens digit
And 10y+x= the number 

x+y= the sum of the digits 
Now we are told that 10y+x=2(x+y) 1st equation 
We are also told that y=x-7 2nd Equation 
So our equations to solve are: 
(1) 10y+x=2(x+y)
(2) y=x-7 


Hope it helps

The final answer is 3x3+6x2+8x+24+47x−2mark me brainliest

Ithink ghe answer to this question is b just trying to others