Does the following equation have an answer?
2n²=m √m=o {n ∈ n*} {o ∈ n*} {m ∈ n*}
it had wondering for

We see that n is in the set of natural numbers (1,2,3,4,5,...), so of course m should be in the natural numbers. However, we see that 2n^2, when square rooted, is . With n in the natural numbers, the square root of m, or o, can never be a natural number but is always an irrational number. Therefore, this equation has no solutions.

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