Jon is launching rockets in an open field. the path of the rocket can be modeled by the quadratic function h(t) = -16t^2 + 96t, where h(t) is the height in feet any time t in seconds. after how many seconds will the rocket reach a height of 80 feet for the second time

It will reach 80 feet for the second time after 5 seconds.

We set the equation equal to 80 feet:
80= -16t² + 96t

When solving quadratics, we want it equal to 0, so we subtract 80 from both sides:
80-80= -16t² + 96t - 80
0= -16t² + 96t - 80

We use the quadratic formula to solve:

Ibelieve the answer is c i worked it out three times but if my answer is wrong someone correct me