Pls ! part a: if (7^2)^x = 1, what is the value of x? explain your answer. part b: if (7^0)^x = 1, what are the possible values of x? explain your answer. will give brainliest

Answers:
Part A: The value of x is 0.
Part B: X can be any real number.

In Part A, you have to first evaluate 7^2. This is 49. Now, write the equation 49^x = 1. We know that if you raise any number to 0, then the answer is 1.

In Part B, you have to first evaluate 7^0, that is 1. Now, we have the equation 1^x = 1. In this case, 1 raised to any exponent is still only 1. Imagine 1^17, this would be 1 times itself 17 times or just 1.

Therefore any number will work in Part B.

Dang i wish i could , good luck (i’m bad at math)