Plz , graph it then for brainliest graph the quadratic function f(x)=x^2−12x+27. graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

See attached picture for solution and graph

f(x)=x^2−12x+27
find Vertex (h, k)
x = h= -b/2a = -(-12)/2(1) = 6
k = f(h) = 36 - 12(6) + 27
k = -9

so vertex (6,-9)

 y = a(x - h)^2 + k

so
y = (x - 6)^2 - 9
x intercept when y = 0
x^2−12x+27 = 0
(x - 9)(x - 3) = 0
x - 9 = 0; x = 9
x - 3 = 0; x = 3
so x-intercept (9,0); (3,0)

y intercept when x = 0 so y = 27  (0, 27)

OK now you can use these to graph the function
(6, -9) (9,0) and (3,0)

Answer: caught punk xd