99 points i will mark brainiliest: given: abcd rhombus, ac: bd = 4: 3 perimeter abcd = 20 cm find: area of abcd

Given that the perimeter of rhombus ABCD is 20 cm, the length of the sides will be:length=20/4=5 cmthe ratio of the diagonals is 4:3, hence suppose the common factor on the diagonals is x such that:AC=4x and BD=3xusing Pythagorean theorem, the length of one side of the rhombus will be:c^2=a^2+b^2substituting our values we get:5²=(2x)²+(1.5x)²25=4x²+2.25x²25=6.25x²x²=4x=2hence the length of the diagonals will be:AC=4x=4×2=8 cmBD=3x=3×2=6 cmHence the area of the rhombus wll be:Area=1/2(AC×BD)=1/2×8×6=24 cm^2