How much would $300 invested at 4% interest compounded monthly be worth after 8 years? round your answer to the nearest cent. here's the equation: a(t)=p(1+r/n)^nt i just don't know what to put where ,

The equation you have provided is correct:

A(t)=P(1+r/n)^nt

Where P = principal amount

              r = interest rate

              n = number of times the amount is compounded in a year

              t = time in years

The value of n is 12 since it is compounded monthly.

Substituting the amount to the formula:

A(t) = $300 ( 1 + 4%/12)^(12)(8)

A(t) = $300 (1 + 0.003333)^96

A(t) = $300 (1.376351)

A(t) = $412.91

0 is its x and y coordinate

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6