Find the absolute maximum and minimum values of the following function on the given interval. if there are multiple points in a single category list the points in increasing order in x value and enter n in any blank that you don't need to use. f(x)=9x^3−27x+9, [0,3],

First we find the critical points by taking the first derivative and setting it equal to zero. So y'=27x^2-27=27(x^2-1)=27(x+1)(x-1)=0. The critical points are x=-1 and x=1. But we have a closed interval here and x=-1 is not in that interval. We must check the values of the endpoints and x=1, the critical point. We substitute those back into the original and get y(0)=9, y(1)=9-27+9=-9 and y(3)=9(3)^3-27*3+9=171. When it asks for values, it is asking for y values. The absolute minimum is -9 and the absolute maximum value is 171.

You must find the surface of the block therefore 98187 dived by 5628 = 583m squared

$18.25 ($365 divided by 20)