Adealer dealt the following cards from a shuffled deck:

3 , 2 , 2 , a , k , q , k , 5 , 2 , 6
4 , 5 , k , 2 , 7 , 6 , a , j , j , a

what was the experimental probability of dealing a black card?

can someone will give medal 8 cards are black and12 are red plesseee do i divide 20 by 8 or 8 by 20,

Well we know that there are 20 cards as given by the equation. And there are 8 black cards.

8/20= .40 or 40% the answer for me is C. 40%

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

%40

step-by-step explanation: