Fan for everyone who , medal for whoever the most! : ) 1. what is the sum of the polynomials? (m + n + 3) + (m + n + 4) 2. which expression can be used to find the difference of the polynomials? (10m – 6) – (7m – 4) 3. which expression can be used to find the difference of the polynomials? (4m – 5) – (6m – 7 + 2n),

1- The sum is: 2m + 2n + 7 = 2(m+n) + 7

2- The difference is: 3m - 2

3- The difference is: -2m - 2n + 2 = -2(m+n-1)

Explanation:

Before we begin, remember the following:

+ve * +ve = +ve

-ve * -ve = -ve

+ve * -ve = -ve

-ve * +ve = -ve

Also, remember that, we only add/subtract like terms. There are terms which have the same variable(s) raised to the same degree

Now, let's check the problems:

Problem 1:

Adding two polynomials:

(m + n + 3) + (m + n + 4)

We first start by getting rid of the brackets:

m + n + 3 + m + n + 4

Now, we add like terms:

2m + 2n + 7

As an additional step, we can take 2 as a common factor from the first two terms:

2(m+n) + 7

Problem 2:

Subtracting two polynomials:

(10m - 6) - (7m - 4)

We first start by getting rid of the brackets. Take care of the different signs while doing so:

10m - 6 - 7m + 4

Now, we add/subtract like terms:

3m - 2

Problem 3:

Subtracting two polynomials:

(4m - 5) - (6m - 7 + 2n)

We first start by getting rid of the brackets. Take care of the different signs while doing so:

4m - 5 - 6m + 7 - 2n

Now, we add/subtract like terms:

-2m - 2n + 2

As an additional step, we can take -2 as a common factor from the above expression:

-2(m+n-1)

Hope this helps :)

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: